ln(1/x^2)

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Solution for ln(1/x^2) equation: 


D( x )

1/(x^2) <= 0

x^2 = 0

1/(x^2) <= 0

1/(x^2) <= 0

1*x^-2 <= 0

1*x^-2 <= 0 // : 1

x^-2 <= 0/1

x^-2 <= 0

1/(x^2) <= 0

x <> 0

1/(x^2) <= 0 // * x^4

(x^4)/(x^2) <= 0

x^2 <= 0

x belongs to the empty set

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

ln(1/(x^2)) = 0

ln(1/(x^2)) = ln(e^0)

1/(x^2) = e^0

1/(x^2)-e^0 = 0

1*x^-2 = 1 // : 1

x^-2 = 1

-2 < 0

1/(x^2) = 1 // * x^2

1 = 1*x^2 // : 1

1 = x^2

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in { 1, -1 }

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